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Free PDF 2025 1z0-071: Marvelous Oracle Database SQL Online Tests

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Oracle Database SQL Sample Questions (Q280-Q285):

NEW QUESTION # 280
View the Exhibit and examine the structure of the PRODUCTS table. (Choose the best answer.) You must display the category with the maximum number of items.
You issue this query:
SQL > SELECT COUNT(*), prod_category_id
FROM products
GROUP BY prod_category_id
HAVING COUNT(*) = (SELECT MAX(COUNT(*)) FROM porducts);
What is the result?

  • A. It generate an error because the subquery does not have a GROUP BY clause.
  • B. It executes successfully and gives the correct output.
  • C. It executes successfully but does not give the correct output.
  • D. It generates an error because = is not valid and should be replaced by the IN operator.

Answer: A


NEW QUESTION # 281
Examine this SQL statement:

Which two are true?

  • A. The UPDATE statement executes successfully even if the subquery selects multiple rows.
  • B. The subquery is not a correlated subquery.
  • C. The subquery is executed for every updated row in the ORDERS table.
  • D. The subquery is executed before the UPDATE statement is executed.
  • E. All existing rows in the ORDERS table are updated.

Answer: A,C


NEW QUESTION # 282
Which two statements are true about the SET VERIFY ON command?

  • A. It displays values for variables used only in the WHERE clause of a query.
  • B. It displays values for variables created by the DEFINE command.
  • C. It can be used only in SQL*plus.
  • D. It displays values for variables prefixed with &&.
  • E. It can be used in SQL Developer and SQL*Plus.

Answer: B,E

Explanation:
The SET VERIFY ON command is related to how SQL*Plus and SQL Developer display information about substitution variables:
* A. It displays values for variables created by the DEFINE command: When VERIFY is set to ON, SQL*Plus and SQL Developer will display the old and new values of a substitution variable when it is redefined using the DEFINE command or when a new value is provided for it during the session.
* B. It can be used in SQL Developer and SQL*Plus: While traditionally associated with SQL*Plus, the SET VERIFY command is also supported in SQL Developer, allowing you to control the display of substitution variable values in both environments.
References:
* Oracle SQL*Plus User's Guide and Reference, especially the section on the SET command and
* substitution variables.


NEW QUESTION # 283
View the Exhibit and examine the structure of the SALES and PRODUCTS tables. (Choose two.)

In the SALES table, PROD_ID is the foreign key referencing PROD_ID in the PRODUCTS table. You must list each product ID and the number of times it has been sold.
Examine this query which is missing a JOIN operator:
SQL > SELECT p.prod_id, count(s.prod_id)
FROM products p ______________ sales s
ON p.prod_id = s.prod_id
GROUP BY p.prod_id;
Which two JOIN operations can be used to obtain the required output?

  • A. JOIN
  • B. RIGHT OUTER JOIN
  • C. LEFT OUETR JOIN
  • D. FULL OUTER JOIN

Answer: C,D


NEW QUESTION # 284
View the exhibit and examine the structure in ORDERS and ORDER_ITEMS tables.

You need to create a view that displays the ORDER_ID, ORDER_DATE, and the total number of items in each order.
Which CREATE VIEW statement would create the view successfully?

  • A. CREATE OR REPLACE VIEW ord_vuAS SELECT o.order_id, o.order_date,
    COUNT(i.line_item_id)FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id,o.order_date;
  • B. CREATE OR REPLACE VIEW ord_vuAS SELECT o.order_id, o.order_date,
    COUNT(i.line_item_id)"NO OF ITEMS"FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id,o.order_date;
  • C. CREATE OR REPLACE VIEW ord_vuAS SELECT o.order_id, o.order_date,
    COUNT(i.line_item_id)||'NO OF ITEMS'FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id,o.order_dateWHITH CHECK OPTION;
  • D. CREATE OR REPLACE VIEW ord_vu (order_id, order_date)AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)"NO OF ITEMS"FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id, o.order_date;

Answer: B


NEW QUESTION # 285
......

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